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(C) The reaction involves the addition of $HBr$ to an alkene in the presence of a peroxide,which follows the Anti-Markovnikov addition rule (Kharasch

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$BrCH_2-CH_2(CH_2)_8COOH$

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(C) The reaction involves the addition of $HBr$ to an alkene in the presence of a peroxide,which follows the Anti-Markovnikov addition rule (Kharasch effect).In this mechanism,the $Br^{\bullet}$ radical attacks the terminal carbon atom of the double bond to form a more stable secondary radical.Consequently,the hydrogen atom attaches to the internal carbon atom.The final product is $BrCH_2-CH_2(CH_2)_8COOH$.

The principal organic product formed in the reaction given below is
$CH_2 = CH(CH_2)_8COOH + HBr \xrightarrow{\text{peroxide}} ....$

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The principal organic product formed in the reaction given below is$CH_2 = CH(CH_2)_8COOH + HBr \xrightarrow{\text{peroxide}} ....$